1. The problem statement, all variables and given/known data A solid sphere of brass (bulk modulus of 14.0*10^10 N/m^2) with a diameter of 3.00 m is thrown into the ocean. By how much does the diameter of the sphere decrease as it sings to a depth of 1.0 km? 2. Relevant equations Gauge pressure = density(water)*g*h Bulk Modulus = -(ΔP/ΔV)*V 3. The attempt at a solution I tried solving for ΔP = gauge pressure = 1000*9.81*1000=9.81*10^6. I then isolated ΔV = -ΔP*V/B V = 4/3*pi*r^3 = 14.14 m^3 I plugged in and got 9.906*10^-4 m^3. I then solved for r in v=4/3*pi*r^3 (where I took V to be equal to 9.906*10^-4). The answer I am getting for r is 6.18cm, which would be a difference of 12.36 cm when considering the diameter. But the answer is 0.0721 mm. Any help would be appreciated. Thanks!