1. The problem statement, all variables and given/known data A moonshiner produces pure ethanol (ethyl alcohol) late at night and stores it in a stainless steel tank in the form of a cylinder 0.290 m in diameter with a tight-fitting piston at the top. The total volume of the tank is 275 L(0.250 m3) . In an attempt to squeeze a little more into the tank, the moonshiner piles lead breaks of total mass 1420kg on top of the piston. a)What additional volume of ethanol can the moonshiner squeeze into the tank? (Assume that the wall of the tank is perfectly rigid.)? 2. Relevant equations v'=-kv0p' where ' means change p'=F/A 3. The attempt at a solution okay the value of k for ethyl is 111x10-6 atm-1 p'=F/A=mg/pir2=1420*9.8/pi(0.145)2=210211.48 v'=-(111x10-6)(0.250m3)(210211.48)=-5.83x10-2m3=58.3L (we can ommit negative because question asks what additional ammount of volume can be added.) Now using this method I still have the wrong answer, Can anyone please point in the right direction. Any help is appreciated.