- #1

tsdemers

- 3

- 0

Can someone help me out on where to get started? It's confusing how the question tells you the speed of the bullet but then says the speed isn't known.

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- Thread starter tsdemers
- Start date

- #1

tsdemers

- 3

- 0

Can someone help me out on where to get started? It's confusing how the question tells you the speed of the bullet but then says the speed isn't known.

- #2

hypermorphism

- 506

- 1

- #3

stunner5000pt

- 1,455

- 2

along came a bullet of some momentum. I'm sure the bullet embeds itself into the block. SO after the bullet struck the block, they both have some common velocity. ow for the energy part.

The velocity has some associated kinetic energy, which was all converted into the spring's energy. Form the relations based on this

- #4

Nenad

- 698

- 0

[tex] PE_{spring} = \frac{1}{2}kx^2 [/tex]

[tex] KE_{system} = \frac{1}{2} (m_{bullet} + m_{block})v_{system}^2 [/tex]

Very simple.

Regards,

Nenad

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