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Bullet fired upwards

  • Thread starter espenth
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  • #1
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A bullet fired vertically upwards with a beginning speed 70 m / s. In this task, we shall assume that the sphere is exposed to air resistance is proportional to the speed, and given by. Proportionality constant k = 1.6 * 10 ^ -2 kg / s and the bullets mass m = 0.100 kg. We expect that the acceleration due to gravity is constant g = 9.81 m/s2.

a) Calculate how high the ball is coming, and how long it takes to peak.

b) What speed is the bullet when it comes back to the starting point, and how long does it take from the vertex to the starting point? What is the acceleration, then?

I guess I have to use integration on the air resistance, but I dont know how to start on this question. Anyone got a sugestion?
 

Answers and Replies

  • #2
ehild
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Perhaps you start with Newton's second law?

ehild
 
  • #3
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I know about newtons law..

In free fall, with air resistance, the equation is something like:

m*g - k*v = m*dV/dT.

But this is for free fall, I guess the one I need is a little bit different?
 
  • #4
ehild
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It is almost the same, but take care of the signs. If the bullet goes upward, both gravity and air resistance point downward.

ehild
 

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