1. The problem statement, all variables and given/known data A bullet of mass 0.0022 kg initially moving at 504 m/s embeds itself in a large fixed piece of wood and travels 0.72 m before coming to rest. Assume that the acceleration of the bullet is constant. What force is exerted by the wood on the bullet? F=N 2. Relevant equations Ok, so I need to find acceleration to plug into the equation for force, which is F=m*a. The equation I am using is x=x0 + v0*t + .5*a*t^2. 3. The attempt at a solution x=x0 + v0*t + .5*a*t^2 so this equation need to be set to solve for a. This is what I am plugging in: x0 = 0 v0 = 504 t = 0.0014 (from d/s = t) My answer is a = 0.706 The equation vf^2 = v0^2 + 2a (delta x), and set to solve for a but I am a bit confused about delta x? In this equation, vf = 0.72 and v0 = 504 I am either having trouble setting up the first equation for a, or I am using the wrong one in which case, I am not sure by what is meant by delta x in the second. Some direction is appreciated!