A 10.0-g bullet traveling at 200 m/s strikes a fixed wooden block. The bullet comes to rest 22 cm inside the block. The magnitude of the force exerted on the bullet by the block over its 22-cm travel is shown in graph below. Find the value of Fmax.(adsbygoogle = window.adsbygoogle || []).push({});

my attempt:

p=mv=(0.01kg)(200m/s)=2J

(.22m)/(200m/s)=0.0011s

(0.0011/2)(fmax)+(.5)(0.0011/2)(fmax)=2J

----rectangle----------triangle--------total area----

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# Homework Help: Bullet in the block

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