1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Bullet meets Gravity

  1. Oct 27, 2008 #1
    1. The problem statement, all variables and given/known data
    A horizontal rifle is fired at a bull's-eye. The muzzle speed of the bullet is 785 m/s. The barrel is pointed directly at the center of the bull's-eye, but the bullet strikes the target 0.029 m below the center. What is the horizontal distance between the end of the rifle and the bull's-eye?

    2. Relevant equations
    Kinematic Equations

    3. The attempt at a solution
    I tried creating a right triangle with the data but it didn't work and now im frustrated.
  2. jcsd
  3. Oct 27, 2008 #2
    use the equation delta d = v(i)t + .5at^2

    delta h (vertical) = .5at^2 where a is -9.81 m/s^2 [since v(i) in the vertical direction is 0)

    -.029 = (.5)(-9.81)t^2


    so you can solve for time and plug it into the equation again to get horizontal distance, right?

    delta d (horizontal) = v(i)t [note, there is no acceleration in the horizontal direction)

    where v(i) 785 m/s
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook