I have a question that reads "A container of water is placed on a scale and the scale reads 120g. Now a 20 g piece of copper (specific gravity = 8.9) is suspended from a thread and lowered into the water but does not touch the bottom of the container. What will the scale now read round off to the nearest whole number?" This has to do with buoyancy force, but I'm not sure what to do here. The buoyancy force is equal to the amount displaced, so is it equal to 20g? Can someone help me get started on this one?