A cube of ice whose edge is 17.0 mm is floating in a glass of ice-cold water with one of its faces parallel to the water surface.
Ice-cold ethyl alcohol is gently poured onto the water surface to form a layer 5.00 mm thick above the water. When the ice cube attains hydrostatic equilibrium again, what will be the distance from the top of the water to the bottom face of the block?
W = mg
V = lwh
The Attempt at a Solution
Here is my work. I have checked and rechecked it, but for some reason it's still not correct! Please help!
mg = FBalcohol + FBwater
m = ρalcoholValcohol + ρwaterVwater
ρiceV = ρalcoholValcohol + ρwaterVwater
934 x 173 = 789 x 172 x 5 mm + 1000 x 172 x h
934 x 17 = 789 x 5 + 1000h
h = 11.933 mm