1. The problem statement, all variables and given/known data -A thin spherical shell of mass 0.300 kg and diameter 0.250 m is filled with alcohol ( = 806 kg/m3). It is then released from rest on the bottom of a pool of water. Find the acceleration of the alcohol filled shell as it rises toward the surface of the water. 2. Relevant equations FB-(M1+M2)g=(M1+M2)a 3. The attempt at a solution M1=0.3kg, r=0.125 m, V= (4*pi*r^3) /3, M2 = pV = (806*V), FB = pVg = (1000)(V)(9.8) . After finding FB, I plugged it back into the equation and got 2.211 m/s^2. This answer was wrong, could someone please tell me if I am using the wrong equation, or if I just screwed something up.