# Buoyant Force on a man

## Homework Statement

A certain man has a mass of 85.0 kg and a density of 995 kg/m3 (exclusive of the air in his lungs).
(a) Calculate his volume.
.0854 m3
(b) Find the buoyant force air exerts on him.
N
(c) What is the ratio of the buoyant force to his weight?
(buoyant force / weight)

## Homework Equations

Fb=density (of substance) x Volume (of object) x g
density of air=1.2 kg/m3

## The Attempt at a Solution

Fb=(1.2 kg/m3) x (9.8) (.0854)
=1.004N

and then for part c
1.004/ (9.8 x 85=833)=.00121

For some reason this is incorrect. Does anyone see why?

kuruman
Homework Helper
Gold Member
Fb=(1.2 kg/m3)x (9.8) (.0854)
A certain man has a mass of 85.0 kg and a density of 995 kg/m3
Incorrect density.

Edit: Sorry I misread the question.

Last edited:
FactChecker
Gold Member
For the buoyant force of the displaced air, the air density should be used as the OP shows. How far off is the answer? Could it be just due to rounding of 1.225 to 1.2?

Yes, I tried that as well and obtain 833N, which is also incorrect. I did this first, and then thought we need to use the density of the air.

For the buoyant force of the displaced air, the air density should be used as the OP shows. How far off is the answer? Could it be just due to rounding of 1.225 to 1.2?

yes, I tried 1.225 and 1.2. Both are incorrect.

FactChecker
Gold Member
yes, I tried 1.225 and 1.2. Both are incorrect.
Just so we don't have to keep guessing, what is the answer given?

Just so we don't have to keep guessing, what is the answer given?

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