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Buoyant force problem. Plz help.

  1. Apr 9, 2008 #1
    1. The problem statement, all variables and given/known data

    Iceberg area: 3.10x10^4 km^2, Flat top and bottom.
    Submerged part .84 km.
    Water density: 1.035x10^3

    what is the buoyant force acting on the iceberg?

    2. Relevant equations

    Fb=Fg pf object of subject = P0V0g
    PfVfg=Weight of displaced fluid=p0v0g=weight of object
    Vu=v0-vf=v0-(p0v0g/pfg)=v0(1-(po/pf)

    I have spend now over 2 hours trying to solve this problem, but no success... Can any help me solve it... driving me crazy..
    Thanks in advance..
     
  2. jcsd
  3. Apr 9, 2008 #2
    If the area you mentioned is the area of cross section of the iceberg. Assuming that the iceberg has uniform shape, the volume of iceberg submerged= Iceberg area*Submerged part
    the volume of water displaced will be=volume of iceberg submerged= Iceberg area*Submerged part

    Buoyant force acting on it=Weight of water displaced=Volume of water displaced*density of water

    I wonder if it helps!!
     
  4. Apr 9, 2008 #3
    Thanks, I was over-thinking it and i cannot believe it is so simple.
     
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