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Buoyant force problem. Plz help.

  • Thread starter Milad_1989
  • Start date
  • #1
1. Homework Statement

Iceberg area: 3.10x10^4 km^2, Flat top and bottom.
Submerged part .84 km.
Water density: 1.035x10^3

what is the buoyant force acting on the iceberg?

2. Homework Equations

Fb=Fg pf object of subject = P0V0g
PfVfg=Weight of displaced fluid=p0v0g=weight of object
Vu=v0-vf=v0-(p0v0g/pfg)=v0(1-(po/pf)

I have spend now over 2 hours trying to solve this problem, but no success... Can any help me solve it... driving me crazy..
Thanks in advance..
 

Answers and Replies

  • #2
580
0
1. Homework Statement

Iceberg area: 3.10x10^4 km^2, Flat top and bottom.
Submerged part .84 km.
Water density: 1.035x10^3

what is the buoyant force acting on the iceberg?

2. Homework Equations

Fb=Fg pf object of subject = P0V0g
PfVfg=Weight of displaced fluid=p0v0g=weight of object
Vu=v0-vf=v0-(p0v0g/pfg)=v0(1-(po/pf)

I have spend now over 2 hours trying to solve this problem, but no success... Can any help me solve it... driving me crazy..
Thanks in advance..
If the area you mentioned is the area of cross section of the iceberg. Assuming that the iceberg has uniform shape, the volume of iceberg submerged= Iceberg area*Submerged part
the volume of water displaced will be=volume of iceberg submerged= Iceberg area*Submerged part

Buoyant force acting on it=Weight of water displaced=Volume of water displaced*density of water

I wonder if it helps!!
 
  • #3
Thanks, I was over-thinking it and i cannot believe it is so simple.
 

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