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Buoyant Force Project

  1. Jan 31, 2008 #1
    1. The problem statement, all variables and given/known data
    Ok so we put a block of wood into water, let it float, then put a 100g weight on the side of it.
    Explain why the block tips and the weight falls off


    2. Relevant equations
    Torque=Fd
    Fb=pvg
    Fg=mg
    Fd>Fb


    3. The attempt at a solution

    ok i know that the Force*Distance if the torque from the center of the block to where the weight is put, and that this force is greater than the buoyant force when it tips, however what would the new Volume be? since the block pivots on its center when the torque is applied, isnt there a new length? i was thinking that the new length is perpendicular to the line of the torque, but how would you express this?
     
  2. jcsd
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