A 9 cm square wooden post (density=420kg/m3) is 1.3m long and floats in sweater (density=1029 kg/m3. How deep is the post submerged in the water? The picture shows a 9cm x 9cm cross section of the post.
Fb=density of liquid x volume of liquid submerged x gravity
Fmg=density of post x volume of post x gravity
P=density x gravity x height
The Attempt at a Solution
I first found the force mg.
420 x (.09x.09x1.3) x 9.8=.103194 N
Then I found pressure
I don't think this is right, and I am unsure where to next. Can anyone help me understand how I should be doing this?