- #1
resjsu
- 12
- 0
Hello All,
At work we will begin press fitting bushings into iron components.
The customer has specified a range for the "push-in" and "pull-out" force so we bought a load cell to measure the values.
My question is, when we approximate force on our standard 50-ton press with a 4inch diameter cylinder head, we multiply the psi by the area of the cylinder head and arrive at a force. So, if the surface area were smaller than the resulting force would be less correct?
Now then referring to the attached drawing, since our arbor is smaller in diameter than our cylinder head and load cell, is the force that is actually being applied to the bushing less than the force being applied to the load cell?
With this setup will the load cell accurately measure the force the bushing is experiencing?
What is wrong with my understanding of pressure/force and how the diameters affect each measurement?
Thank you for your help and time!
At work we will begin press fitting bushings into iron components.
The customer has specified a range for the "push-in" and "pull-out" force so we bought a load cell to measure the values.
My question is, when we approximate force on our standard 50-ton press with a 4inch diameter cylinder head, we multiply the psi by the area of the cylinder head and arrive at a force. So, if the surface area were smaller than the resulting force would be less correct?
Now then referring to the attached drawing, since our arbor is smaller in diameter than our cylinder head and load cell, is the force that is actually being applied to the bushing less than the force being applied to the load cell?
With this setup will the load cell accurately measure the force the bushing is experiencing?
What is wrong with my understanding of pressure/force and how the diameters affect each measurement?
Thank you for your help and time!