Butis really so easy? (Möbius inversion)

  • Thread starter tpm
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  • #1
tpm
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But..is really so easy? (Möbius inversion), let be F(x) and G(x) functions

[tex] F(x)= G(ax)+G(2ax)+G(3ax)+............... [/tex]

for n=,1,2,3,4,5,............ a is a fixed real number. then

[tex] G(ax)= \sum_{n=1}^{\infty}\mu (x) F(nx) [/tex]

is seems too easy for me, to be true.
 

Answers and Replies

  • #2
matt grime
Science Advisor
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Why don't you try it? (You might want to make sure you state it properly.)
 

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