Solve the integral of [xln(x^2+9)] wrt x using the tabular method.
By parts using the tabular method.
The Attempt at a Solution
The answer for now is : ((1/2)x^2)ln(x^2+9) -(1/3)[integral of](x^4/(x^2+9))dx
dividing x^4/(x^2+9) gives (x^2)-9+(81/x^2+9)
however integrating 1/(x^2+9) would give a trig function whereas the answer given contains to trig function at all. Where have I gone wrong in my method? Thanks in advance!