# C=1 meaning

1. Oct 9, 2011

### Casco

What is the meaning of a frame of reference where $c=1$ ???

Are these the so called natural units??

And which is the purpose of this??

2. Oct 9, 2011

### Staff: Mentor

It just means that your units of distance and time are such that c=1 in that system of units. E.g. if you measure time in years and distance in lightyears.

Natural units always have c=1, but not all systems where c=1 are natural units.

It makes calculations easier.

3. Oct 9, 2011

### Casco

Can you tell me which is the system of natural units?? Because I have seen G=c=h=1, Is it that??
And, its purpose is just making calculations easier or is it there something else besides that?

4. Oct 9, 2011

### Staff: Mentor

There is no purpose other than making calculations easier:
http://en.wikipedia.org/wiki/Natural_units
http://en.wikipedia.org/wiki/Planck_units
http://en.wikipedia.org/wiki/Heaviside–Lorentz_units
http://en.wikipedia.org/wiki/Stoney_units
http://en.wikipedia.org/wiki/Atomic_units
http://en.wikipedia.org/wiki/Geometrized_unit_system

5. Oct 9, 2011

### Casco

Ok, thanks.

6. Oct 10, 2011

### Phrak

It's also a way cause confusion and misdirection when used carelessly.

As to you opening equation: there aren't any inerital frames of reference with v=c.

7. Oct 10, 2011

### shana parveen

what actually quantum mechanics means? what is it trying to convince us?what is its application?

8. Oct 10, 2011

### Staff: Mentor

Hi shana parveen, welcome to PF!

You probably should post a new thread in the QM sub-forum. This question is fine, but it is off topic for both this thread and this sub-forum. Follow this link
https://www.physicsforums.com/forumdisplay.php?f=62

And click the button labeled "New Topic".

9. Oct 10, 2011

### Staff: Mentor

Actually, I consider it to be extremely vague. I suggest that shana parveen post questions that are more specific, if he hopes to get useful answers.

10. Oct 14, 2011

### Casco

I think these are really hard questions to answer, Feynman sad "You don't understand QM, you just get used to it", What is trying to convince us? Very vague question. And its applications are infinities.