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C-G identity

  1. Feb 23, 2007 #1

    quasar987

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    Hi,

    How can I prove that

    [tex]<J,2;J,0|J,J>=<J,2;-J,0|J,-J>[/tex]

    ?

    (my "template" is [tex]<j_1,j_2;m_1,m_2|JM>[/tex])


    thx
     
  2. jcsd
  3. Feb 25, 2007 #2

    dextercioby

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    Where did you get it from ? I don't think it's correct...
     
  4. Feb 25, 2007 #3

    quasar987

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    It's correct "experimentally" in the sense that I'Ve looked in a C-G table and it's always true.

    And according to a classmate of mine, he went to see the teaching assistant and he told him it was correct.
     
  5. Feb 25, 2007 #4

    nrqed

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    You mean what you wrote, and not
    [tex]<J,2;J,0|J,-J>=<J,2;-J,0|J,J>[/tex], right?
    (at first I thought you had written what I just wrote and I saw a way to prove it easily but I don't see right away how to prove the wone you gave)
     
  6. Feb 25, 2007 #5

    quasar987

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    i mean what i wrote
     
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