C-G identity

1. Feb 23, 2007

quasar987

Hi,

How can I prove that

$$<J,2;J,0|J,J>=<J,2;-J,0|J,-J>$$

?

(my "template" is $$<j_1,j_2;m_1,m_2|JM>$$)

thx

2. Feb 25, 2007

dextercioby

Where did you get it from ? I don't think it's correct...

3. Feb 25, 2007

quasar987

It's correct "experimentally" in the sense that I'Ve looked in a C-G table and it's always true.

And according to a classmate of mine, he went to see the teaching assistant and he told him it was correct.

4. Feb 25, 2007

nrqed

You mean what you wrote, and not
$$<J,2;J,0|J,-J>=<J,2;-J,0|J,J>$$, right?
(at first I thought you had written what I just wrote and I saw a way to prove it easily but I don't see right away how to prove the wone you gave)

5. Feb 25, 2007

quasar987

i mean what i wrote