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C-G identity

  • Thread starter quasar987
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  • #1
quasar987
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Hi,

How can I prove that

[tex]<J,2;J,0|J,J>=<J,2;-J,0|J,-J>[/tex]

?

(my "template" is [tex]<j_1,j_2;m_1,m_2|JM>[/tex])


thx
 

Answers and Replies

  • #2
dextercioby
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Where did you get it from ? I don't think it's correct...
 
  • #3
quasar987
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It's correct "experimentally" in the sense that I'Ve looked in a C-G table and it's always true.

And according to a classmate of mine, he went to see the teaching assistant and he told him it was correct.
 
  • #4
nrqed
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Hi,

How can I prove that

[tex]<J,2;J,0|J,J>=<J,2;-J,0|J,-J>[/tex]

?

(my "template" is [tex]<j_1,j_2;m_1,m_2|JM>[/tex])


thx
You mean what you wrote, and not
[tex]<J,2;J,0|J,-J>=<J,2;-J,0|J,J>[/tex], right?
(at first I thought you had written what I just wrote and I saw a way to prove it easily but I don't see right away how to prove the wone you gave)
 
  • #5
quasar987
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i mean what i wrote
 

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