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C++ output date in number of days per year

  1. Jun 29, 2005 #1
    for example
    user puts in the month as 1-12
    the day for whatever month
    and the year, which has to include leapyears
    leap years only occur when the year is divisible by 4 y%4==o or if divisible by 400 but NOT 100, so 2000 is a leap year but not 2100

    so if somebody puts in month 1 day 1 and 2005 it will say 1
    if it's month 12 and day is 31 and year is 2005 it will say 365
    but if it was 2004 it would say 366
    month 3, day 10, year 2005, would be 31+28+10 or just 69

    can anybody do this
    i guess it needs boolean stuff for the leap year
    and a few switch and case things for the rest

    i'm not feeling it though

    i got one to kind of work with if statements but not correctly, and it was long
     
  2. jcsd
  3. Jun 29, 2005 #2
    Code (Text):

    if (year%4 == 0 && !(year%100 == 0 && year%400 != 0))
        DaysPerMonth = {31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    else
        DaysPerMonth = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

    for (i=0; i<month - 1; i++)
        ndays += DaysPerMonth[i];

    ndays += day;
     
     
  4. Jun 30, 2005 #3
    Well put :)
     
  5. Jun 30, 2005 #4
    and what am i putting in right above that (i've been doing this for less than a month so bear with me)
    i dont know what exactly i am calling what
    int days, etc.???
     
  6. Jun 30, 2005 #5
    pick up a standard C OR C++ book. there are tutorials about such things usual in those or there are websites...sorry I cant remember C++tutorials.com cplus.com i think are some...
     
  7. Jun 30, 2005 #6
    yeah i got a book, but it's no good, or it's too good
     
  8. Jun 30, 2005 #7
    heh I dont think thats a legal URL format, only alpha-numerical chars are allowed :tongue2:
     
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