The 2020 kg cable car shown in the figure descends a 200-m-high hill. In addition to its brakes, the cable car controls its speed by pulling an 1850 kg counterweight up the other side of the hill. The rolling friction of both the cable car and the counterweight are negligible.
If the cable car is descending at a constant speed, then what is the tension in the cable?
newton's 2nd law
The Attempt at a Solution
Since is moving at a constant speed acceleration is zero.
I found the tension equal to the y component of the weight of the cable car (i have the y component being parallel to the ramp).
2020(9.80)sin30 = 9898N
I thought this would be the tension but it's not so i considered the tension in the counterweight as well.
1850(9.8)sin(20) = 6200 N
Would i maybe subtract these to get the tension in the cable?