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Cable tension at an angle

  1. Sep 29, 2008 #1
    A tow truck is connected to a 1500 kg car by a cable that makes a 23o angle to the horizontal. If the truck accelerates at 0.59 m/s2, what is the magnitude of the cable tension? Neglect friction and the mass of the cable.

    i know that the car is accelerating at the same rate. my question is how do you include the angle into the equation for the cable tension?
  2. jcsd
  3. Sep 29, 2008 #2
    I think the purpose of the angle is so that you can de-compose the problems into components, Fx and Fy. Try to resolve both forces on the x-direction and y-direction first
  4. Sep 29, 2008 #3
    I got it

    F= (M * a)/cos (theta)
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