1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Caclulus Triangle Problem

  1. Dec 19, 2008 #1
    1. The problem statement, all variables and given/known data

    The vertices of a triangle are (0,0), (x, cos x), and (sin3x, 0), where 0 < x < p/2.
    a. If A(x) represents the area of the triangle, write a formula for A(x).
    b. Find the value of x for which A(x) is a maximum. Justify your answer.
    c. What is the maximum area of the triangle?

    2. Relevant equations
    I know this involves min/max problems, and the area of a triangle at some point.

    3. The attempt at a solution
    No idea where to start. I don't see any way to get an area function for the triangle.
  2. jcsd
  3. Dec 19, 2008 #2


    User Avatar
    Staff Emeritus
    Science Advisor

    You do know that the area of a triangle if "1/2 base times height", don't you? Draw a picture and see what base and height are for this triangle.
  4. Dec 19, 2008 #3
    So is A(x)= (1/2)(sinx)^3(cosx)? If that's true then do I have to take the derivative or something?
    Last edited: Dec 19, 2008
  5. Dec 20, 2008 #4
    Is it sin3x or (sinx)^3? Once that is cleared up, how would you usually find the maximum of a function? A derivative would help.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Caclulus Triangle Problem
  1. Triangle problem (Replies: 12)