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Cal 3

  1. Nov 21, 2005 #1
    given that near (1,1,1) the curve of intersection of the surfaces:
    x^6 + y^4 + z^7 -3xyz = 0 and
    xy + yz + zx - 3z^4 = 0
    has the paramteric equations x = f(t), y = g(t), z = t with f and g differentiable, how do i find rhe derivatives of f and g?
    and the tangent line to the curve of intersection at (1,1,1)?
     
  2. jcsd
  3. Nov 21, 2005 #2
    [tex]\vec{\mathbf{r}}=f(t)\,\hat{\mathbf{i}}+g(t)\,\hat{\mathbf{j}}+t\,\hat{\mathbf{k}}[/tex]

    What would happen if you plugged these values of x, y, and z into the original two equations?
     
    Last edited: Nov 21, 2005
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