Hey I'm doing something really stupid it is really pissing me off why I can't figure it out.
The Attempt at a Solution
Evaulate the integral : ∫ x(1-x)^1/2
I tried with substitution. u = 1-x , -du = dx and x = 1-u
∫ (1-u)(u)^1/2 I just tried to simplify it some.
∫ (u^1/2-u^3/2) -du
-∫ u^1/2 du +∫ u^3/2 du
integrate I got
(-2/3)u^ 3/2 + (2/5)u^5/2
(-2/3)(1-x)^ 3/2 + (2/5)(1-x)^5/2
My book got (-2/15)*2+3x)(1-x)^3/2 + C
Thanks for the help.