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Calc 2 Integral.

  1. Sep 18, 2014 #1
    1. I need help solving this integral, I've tried using trig substitution, but I'm getting nowhere with it.


    ∫x/(6x-x^2)^3/2dx



    Like I said before, I tried changing the bottom to a radical and trig substituting but it doesn't seem to get me anywhere. Thanks in advanced for any help.
     
  2. jcsd
  3. Sep 18, 2014 #2

    Simon Bridge

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    Welcome to PF;
    You are trying to evaluate the indefinite integral:
    $$\int \frac{x}{(6x-x^2)^{3/2}}\;dx$$

    Note: ##(6x-x^2)^{3/2} = x^{3/2}(6-x)^{3/2}## ... probably won't help a lot: try again but complete the square first.
     
  4. Sep 18, 2014 #3

    vela

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    Please show your work.
     
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