Let f be the functions f(x)=ln(3x+2)^k for some positibe constant k.
If f'(2)=3, what is the value of k?
the answer is 8,but i dont think i am taking the derivative right.
The Attempt at a Solution
then i plugged in (2,3) into the derivative above.
and i got k=8/(ln8)(8^(k-1))