1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Calc AP problem 1

  1. Mar 1, 2004 #1
    Problem: A particle moves along the x-axis so that any time t >_ 0 its velocity is given by v(t) = ln(t + 1) - 2t + 1. What is the total distance traveled by the particle from t=0 to t=2?

    Am I correct that the total distance is the area under the curve? I tried doing the integration on my calculator, and it gave me a negative answer. Then I graphed to make sure I didn't do anything wrong. I don't think I should be getting a negative answer, so..... help please.
  2. jcsd
  3. Mar 1, 2004 #2

    Math Is Hard

    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    I think the problem here is that your particle isn't always moving forward. When you measure total distance, you'll need to determine the intervals where the particle is moving backward (where velocity is negative) and take the absolute value of that distance.
    Just a thought.
  4. Mar 1, 2004 #3
    If it is velocity then area under the curve gives u displacement not distance for calculating distance apply the following formula

    Distance covered from time t=a to t=b is

    [tex]\int_a^{b} |v(t)|dt[/tex]

    Or draw the graph of |v(t)| from the graph of v(t)

    Area under |v(t)| will give u distance
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Calc AP problem 1
  1. AP Problem (Replies: 8)

  2. Ap calc AB problems (Replies: 1)

  3. AP Problem (Replies: 4)

  4. AP Problem (Replies: 1)