# Calc Help: Find Volume of Quadrant & Semicircle

• gigi9
In summary, the problem is talking about a shape that looks like a half a croissant and it is trying to find the volume.

#### gigi9

Plz explain to me what the problem below is talking about? I don't really understand what it's saying...I can't picture the graph of the function...
"The base of a solid is a quadrant of a circle of radius a. Each cross section perpendicular to one edge of the base is a semicircle whose diameter lies in the base. Find the volume."

Sounds like a funny looking shape; kind of like a loaf of bread or something. Anyway, the base is just a quarter of a circle, so you have x^2+y^2 = a^2

Then you've got semicircles in the z-axis (I'm setting these semicircles' diameters parallel to the x-axis.)

To find the volume, I think you just integrate the area of the semicircles along the y-axis:

V = integral( A(r)dy) (limits from 0 to a, x-sectional area A is a function of the radius)
A = (pi r^2)/2 (for each semicircle)
r = x/2 (x is a function of y, this should be clear if you drew it the way I said I did)
and then use the first equation...

I end up with V = (pi a^3)/4, though I'm prone to screwing up algebra

More half a croissant than a loaf of bread but I like that description!
Here's a way to construct it (following what jamesrc said):

Get a thin sheet of styrofoam. Draw a quarter circle on a sheet of paper (with radius a multiple of the thickness of your styrofoam). Mark off points on one radius (say, the horizontal one) of the quarter circle equal to the thickness of the styrofoam. Draw vertical lines at each mark across the quarter circle and measure their length.
Cut out semicircles of styrofoam having those distances as diameter.
Glue the semicircles on the quarter circle- in the correct places, of course.
Take this to class and impress your teacher!

This model is an approximation to the figure. The thinner the styrofoam is in comparison to the radius of your quarter circle (in other words the more multiples of the thickness you make your radius) the "smoother" it will be. Actually, what you have is a model for the "Riemann sums" that define the integral.

Since your quarter circle has radius a, it is part of the graph of
(again, as jamesrc said) x2+ y2= a2. Taking our quarter circle to be the one in the first quadrant, we have y= &radic;(a2- x2) and that will be the "diameter" of the semicircle constructed at x. The radius of that semicircle is then (1/2)&radic;(a2- x2) of course and, since the area of a semicircle is (1/2)&pi;r2, the area of each such semicircle is (1/2)&pi;(1/2)&radic;(a2- x2))= (1/8)&pi;(a2- x2.
Taking the thickness of your "styrofoam" to be &Delta; x, the volume of each semicircular piece is (1/8)&pi;(a2- x2)&Delta;x and the volume of all of them put together is
&Sigma;(1/8)&pi;(a2- x2); Delta; x. That would be the volume of your model- an approximation to the volume of the original figure.

Now the usual limit "magic" gives the exact volume of the original figure and turns the Riemann sum into an integral as (1/8)&pi;&int;(a2- x2)dx where the integral is from x= 0 to x= a. That's an easy integral.

(I get (1/12)&pi;a3. I wonder if jamesrc didn't "screw up" the integral rather than the algebra!)

Good grief. I screwed up the algrebra.
My second to last step was
V = (pi/8)*(a^3 - (a^3/3))
and I managed to get pi*a^3/4

pi*a^3/12 is more like it.

Next time I try to help I promise I won't work the answer out on a napkin.

Absolutely, napkins get wrinkled and that messes up your algebra!

(Plus the fact that I keep spilling coffee on them!)

## 1. What is a quadrant and semicircle?

A quadrant is a quarter of a circle, while a semicircle is half of a circle. They are both curved shapes that are commonly used in geometry and trigonometry.

## 2. Why do we need to find the volume of a quadrant and semicircle?

Calculating the volume of these shapes is important in various applications, such as architecture and engineering. It helps us understand the amount of space or material needed for a specific project.

## 3. How do you find the volume of a quadrant?

To find the volume of a quadrant, you can use the formula V = (πr^2h)/4, where r is the radius of the quadrant and h is the height. This formula is derived from the volume formula of a cone, since a quadrant is essentially a quarter of a cone.

## 4. How do you find the volume of a semicircle?

The formula for finding the volume of a semicircle is V = (πr^2h)/2, where r is the radius of the semicircle and h is the height. This formula is also derived from the volume formula of a cone, since a semicircle is half of a cone.

## 5. Can the volume of a quadrant and semicircle be found using the same formula?

No, the formulas for finding the volume of a quadrant and semicircle are different. The difference lies in the factor used to calculate the volume, as well as the height of the shape. Make sure to use the correct formula when finding the volume of each shape.