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Calc/trig homework help

  1. Sep 18, 2007 #1
    A surveyor stands on flat ground at an unknown distance from a tall building. She measures the angle from the horizonal ground to the top of the building; this angle is pi/3. next she paces 40ft further away from the building. the angle from the ground to the top of the building is now measured to be pi/4.

    i think i got this one right, but im new to the site so i thought i would just check myself with this problem. i got equation 40 + x = y beause the horizontal axis must equal the vertical when the angle is 45 degrees (pi/4). Then i used tan(60) = y/x to solve for x and then i subsituted eventually solving for y. my final answer is 94.8ft. part B asks for the angle if the person moves further back 20 ft. i just added that length to 94.8 and used tan to solve eventually getting the angle to be 39.5 degrees. If anyone has the time can they check the work to make sure i did it correctly? Thanks.
  2. jcsd
  3. Sep 19, 2007 #2


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    Wouldn't it be better to check it yourself? You say that the building has height 94.8 feet. The first distance from building is 94.8- 40= 54.8. Is tan(pi/3)= 94.8/54.8? The last distance is 94.8+ 20= 114.8. Is tan(39.4)= 94.8/114.8?

    By the way, why are you converting from radians (as given) to degrees? Certainly your answer should be given in radians.

    And, of course, this is not in any sense "calculus and analysis". I am moving the thread to "general math".
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