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Hello everyone, I was suppose to show B(t) = T(t) x N(t) is perpendicular to both T(t) and N(t). I'm also to find |B(t)| which is the magnitude of B(t). B stands for a Binormal vector. T is the tagnent unit vector and N is the unit normal. The vector b(t) = T(t) x N(t) is perpendicualr to both T and N and is also a unit vector. Well i got the first part i think, but I don't know how i'm suppose to find the magnitude of B(t), any ideas? Here is my proof and work for the first part, maybe that will help figure out what he wants me to find for part (b).

http://img133.imageshack.us/img133/8076/88eb1.jpg [Broken]

if that link is slow, this one also has my work:

http://show.imagehosting.us/show/764387/0/nouser_764/T0_-1_764387.jpg

Thanks!

Also, i just thought...because it said the binormal vector is also a unit vector, doens't that mean that |B(t)| = 1? Because I know |T(t)| = 1, and T is also a unit vector.

http://img133.imageshack.us/img133/8076/88eb1.jpg [Broken]

if that link is slow, this one also has my work:

http://show.imagehosting.us/show/764387/0/nouser_764/T0_-1_764387.jpg

Thanks!

Also, i just thought...because it said the binormal vector is also a unit vector, doens't that mean that |B(t)| = 1? Because I know |T(t)| = 1, and T is also a unit vector.

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