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Calculas help

  1. Mar 6, 2004 #1
    Show that dy/dx = (a+4b)x^(a+4b-1) if y = x^(2a+3b) / x^(a-b) and a and b are integers



    thx
     
  2. jcsd
  3. Mar 6, 2004 #2
    If you have
    [tex]
    y=\frac{fx}{gx}
    [/tex]
    then
    [tex]
    \frac{dy}{dx}=\frac{gx*(fx)'-fx*(gx)'}{(gx)^2}
    [/tex]
     
  4. Mar 6, 2004 #3

    HallsofIvy

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    Staff Emeritus
    Science Advisor

    Much more simply:
    y = x^(2a+3b) / x^(a-b)
    = x^((2a+3b)-(a-b))
    = x^(a+ 4b)

    Now, what is y'?
     
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