Q1. A cyclist can develop power of 400W and a top speed on a level road of 7.5m/s. The drag force against which the cyclist is working is? Q2. A constant force drags a block of mass 2kg up a smooth slope at a constant speed of 1m/s, exerting power or 10W. The angle of the slope is? 2. P=F x V mgsin(theta) F=ma 3Q1. 400W/7.5m/s = 53.3N (3s.f.) This is just a simple solution stating that the drag force is equal to the forward thrust force, right? As not mention of Frictional Force has been mentioned. 3Q2. If there is a constant force there is no acceleration. Force acting up the slope - P/V = 10/1 = 10N Force acting downwards - mgsin(theta). Now I'm stuck. I think I need to calculate F-F1=mgsin(theta). But I have two missing numbers for this equation. If I try to find acceleration using F=ma I get 10N/2kg = 5ms-2. But if this is a constant force this is no acceleration. Confused. Please help???