(adsbygoogle = window.adsbygoogle || []).push({}); Q1. A cyclist can develop power of 400W and a top speed on a level road of 7.5m/s. The drag force against which the cyclist is working is?

Q2. A constant force drags a block of mass 2kg up a smooth slope at a constant speed of 1m/s, exerting power or 10W. The angle of the slope is?

2. P=F x V

mgsin(theta)

F=ma

3Q1. 400W/7.5m/s = 53.3N (3s.f.)

This is just a simple solution stating that the drag force is equal to the forward thrust force, right? As not mention of Frictional Force has been mentioned.

3Q2. If there is a constant force there is no acceleration.

Force acting up the slope - P/V = 10/1 = 10N

Force acting downwards - mgsin(theta). Now I'm stuck. I think I need to calculate F-F_{1}=mgsin(theta). But I have two missing numbers for this equation. If I try to find acceleration using F=ma I get 10N/2kg = 5ms^{-2}. But if this is a constant force this is no acceleration.

Confused. Please help???

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# Homework Help: Calculate angle of slope

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