A rock at the surface has a density of 2600kg(m^(-3)
90000m down its density is 3100kg(m^(-3)
Change in pressure at the depth is due to hydrostatic pressure.
Whats the bulk modulus of the rock?
Δp=p + ƿgh
The Attempt at a Solution
p(90000)= 1 x 10^(5) Pa + (3100kg(m^(-3))(9.81m/s^(2))(90000m)
Δp= 2.74 x 10^(9) Pa
Δp= - B(ΔV/V)
So, (ΔV/V) => ΔV=m/ƿcompressed
So the 2 m cancel and the expression for the bulk modulus is
B= 3.3 x 10^(9)
I think I may have made a slight misktake please help?