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Calculate leakage resistance

  • Thread starter tommoturbo
  • Start date
  • #1
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1. Calculate the leakage resistance across a capacitor of 100pF that has a relative permittivity of 12 and a resistivitty of rho=10*14



2. Rl=rho x Er x Eo /C
Rl=10*14 x 12 x 8.85*-12 / 100*-12




3. Rl=1.062*15


surley the leakage resistance cant be that high my freind said it should be this formula

You need to use the formula; R = rho E/C (it's the lesson books somewhere!), where E = ErEo.

So, E = ErEo which is; 12*8.85*10^-12. This equals 1.062*10^-10

Therefore R = 1014 * 1.062*10^-10/100*10^-12.

This gives R as 1076.87 ohms.
 

Answers and Replies

  • #2
22
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I calculated

[tex]R_{leak}=1.062\times10^{14}[/tex] ohms

Sure it's a big value - not something you measure with a multimeter! - but an ideal capacitor would have infinite leakage resistance.
 

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