- #1
nautica
A Cl solution with a volume of 13.53 mL was treated with 30.0 mL of Cr3+ solution (containing excess Cr3+) to convert to hexachlorochromateIII:
6Cl- + Cr ----- Cr(Cl)6
The excess Cr3+ was then tirated with 11.85 mL of 0.01280 M (en) according to equation:
Cr + 3en ------------- Cr(en)3
Cr(Cl)6 does not react with en. If 41.35 ML of en were required to react with 20.17 mL of the original Cr3+ solution, calculate the molarity of Cl in the 13.53 mL Chloride sample.
THIS IS WHAT I DID
0.04135 L * 0.01280 M / 3 moles / 0.02017 L * 0.03 L * 6 mol Cl / 0.01353 L with an answer of 0.1164 M Cl- in solution
my problem is - no where did I include the 11.85 mL of the en that was calculated. Do I need to or does this look correct?
Thanks
Nautica
6Cl- + Cr ----- Cr(Cl)6
The excess Cr3+ was then tirated with 11.85 mL of 0.01280 M (en) according to equation:
Cr + 3en ------------- Cr(en)3
Cr(Cl)6 does not react with en. If 41.35 ML of en were required to react with 20.17 mL of the original Cr3+ solution, calculate the molarity of Cl in the 13.53 mL Chloride sample.
THIS IS WHAT I DID
0.04135 L * 0.01280 M / 3 moles / 0.02017 L * 0.03 L * 6 mol Cl / 0.01353 L with an answer of 0.1164 M Cl- in solution
my problem is - no where did I include the 11.85 mL of the en that was calculated. Do I need to or does this look correct?
Thanks
Nautica