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Im working on my chemistry work, i just completed an experiment.. Heat of Reaction. Now I am working on some questions for it... now I am stuck

They are asking me, The amount of NaOH moles... I am not sure how to calculate this... throughout the experiment i was mixing 5.5g of NaOH to 200mL of water and to begin with I made a solution 4.00ml 1.0mol/L NaOH solution. Hmm well i have three tables to fill out for 3 different reactions Ill show just the results for the first one, and if someone could help me with this one I am sure i could figure out the other two.

Initial temperature of water: 25 C

Final Temperature of water: 30 C

Mass of NaOH: 5.5g

Volume of water 200mL

Temperature change: 6 C

Mass of solution: 200g ( since i had 1.0mol/L solutions)

Heat change: 5.016kJ (used equation deltaH=m * delta T* Q (which i was given to be 4.18 x 10^-3 kJ/g C

Now i need the amount of NaOH(moles)

and Average H (kj/mol NaOH)

CAN SOMEONE PLEASE HELP ME ON HOW TO FIND THESE PLEASE?