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Introductory Physics Homework Help
Calculate net charge with nonuniform electric field
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[QUOTE="ooohffff, post: 5558475, member: 598994"] [h2]Homework Statement [/h2] In a cubical volume, 1.05 m on a side, the electric field is given by the formula below, where [I]E[SUB]0[/SUB][/I] = 1.25 N/C and [I]a[/I] = 1.05 m. [ATTACH=full]203071[/ATTACH] = [I]E[SUB]0[/SUB][/I](1 + [I]z[/I]/[I]a[/I]) i + [I]E[SUB]0[/SUB][/I]([I]z[/I]/[I]a[/I]) j The cube has its sides parallel to the coordinate axes, see the figure. Determine the net charge within the cube. [ATTACH=full]203072[/ATTACH][h2]Homework Equations[/h2] φ[SUB]e[/SUB] = ∫E⋅dA = q[SUB]enc[/SUB]/ε[SUB]0[/SUB] [h2]The Attempt at a Solution[/h2] [/B] So I know that I need to calculate the net flux through all the 6 faces of the cube in order to solve for q[SUB]enc[/SUB]. I know that φ[SUB]+z[/SUB] and φ[SUB]-z[/SUB] are equal to 0. I think I am doing something wrong because it seems like they would cancel out? φ[SUB]+x[/SUB] = E[SUB]0[/SUB] a[SUP]2[/SUP] ∫ (1+z/a) dz φ[SUB]-x[/SUB] = -E[SUB]0[/SUB] a[SUP]2 [/SUP] ∫ (1+z/a) dz φ[SUB]+y[/SUB] = E[SUB]0[/SUB] a[SUP]2 [/SUP] ∫ (z/a) dz φ[SUB]-y[/SUB] = -E[SUB]0[/SUB] a[SUP]2 [/SUP] ∫ (z/a) dz Also, I would evaluate the integrals from 0 to a right? [/QUOTE]
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Introductory Physics Homework Help
Calculate net charge with nonuniform electric field
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