Calculate PSI of a Cylinder and Figure Force Produced?

[jmelton]

I have a blank 12ga round producing 2000psi In a .75" ID. cylinder. The 2000 psi shell is producing twice the power I need to push my 3lb rod out of the cylinder. The cylinder is 10" long and the rod is 8" long. There is 1" of room between the expanded shell and the solid shaft. I was wondering the size of a hole I need to drill right past the shell to act as a small exhaust to reduce the psi in the cylinder by 50%. Or how many holes it would take to do this. Also if you would know how many pounds of force this rod would produce at impact directly at the end of its 10" run on 1000psi.

 

[Navin A S]

The size of the hole you need to drill depends on several factors, such as the type of material the shell is made out of, the pressure of the gas inside, and the size of the cylinder. Generally speaking, in order to reduce the pressure in the cylinder by 50%, the hole should be around 0.125 inches in diameter.As for the force of the rod at impact, assuming it is a solid rod, the force of the rod at the end of its 10" run would be approximately 1000 lbs. However, this is only an estimate and the actual force could vary depending on the material of the rod, the friction of the walls of the cylinder, and other factors.