1. The problem statement, all variables and given/known data Calculate the room temperature by using the speed of sound formula and using the given values. Known Data: Frequency = 480 Hz 2nd Resonant length = 54cm or 0.54m 2. Relevant equations v = 331 + (0.60)T T = (v - 331)/0.60 v = fλ (Open-Closed air column) L = (3/4)λ 3. The attempt at a solution (1) v = fλ = 480Hz (0.53m) = 254.4m/s (2) T = (254.4m/s) - 331 / 0.60 = -127.6 degrees celcius I highly doubt the temperature is this low. I realized that I used the wavelength as the resonant length so, I decided to solve for λ using the resonant length. I did the same process again but using the calculated λ but it didnt work either.