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Homework Help: Calculate simple equation

  1. Apr 22, 2007 #1
    Hi i have to read mathematics over 7 years and now i cant even solve a simple equation
    1. The problem statement, all variables and given/known data
    I hav3e the following
    x(t)=-3t for t<0 and
    x(t)=t t>=0
    I want to calculate the x(t)+x(-t) for t<0 firstloy and then for t>=0

    2. Relevant equations


    3. The attempt at a solution
    For t<0
    x(t)+x(-t)=-3t+t (x(t)=-3t cause x is negative x(-t)=t cause the negative of the negative -t is the t which is t)
    The problem is that my teachers book says that x(t)+x(-t)=-3t-t and i cant understand how he calculates that

    Now for t>=0 x(t)+x(-t)=t-3t (x(t)=t cause it is positive and x(-t)=-3t cause the negative of t>=0 is the t<0 which makes x(t)=-3t..
    My teacher again argues with me cause he calculates in his note
    x(t)+x(-t) as =t+3t
    So what i am doing wrong ?:(
     
  2. jcsd
  3. Apr 22, 2007 #2

    AKG

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    Homework Helper

    Since t < 0, it follows that -t > 0, hence x(-t) = -t. I can't understand your reasoning for why x(-t) = t when t < 0.
    t is not necessarily positive. It could be exactly 0.
    Again, I don't know what you're doing. When t is non-negative, -t is non-positive, so either -t = 0 or -t < 0. If -t = 0, then x(-t) = 0 = 3(0) = 3t. If -t < 0, then x(-t) = -3(-t) = 3t.
     
  4. Apr 22, 2007 #3
    thx for your answer one more question then
    y(t)=2t+2 for -1<=t<0
    y(-t)=-2t+2 for ??? i first multiple with - or first i convert the > to < ?
     
  5. Apr 22, 2007 #4

    HallsofIvy

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    If y(t)=2t+2 for -1<=t<0 is the only definition you are given, then in order to be able to find f(-t) using that definition you must have, multiplying each part by -1, -(0)< -(-t)<= -(-1). In other words, 0< t< 1. And, in that case, y(-t)= 2(-t)+ 2.
     
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