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Calculate tension if acceleration given

  1. Jun 15, 2005 #1
    a 70.0 kb man climbs vertical rope attached to ceiling. weight of rope is neglected. calculate tension in rope, if accelerate up rope at 0.40 m/s^2

    T = m(g+a)
    T = 70.0(9.8+.4)
    = 714 N

    slides downward acceleration of .40
    T = m(g-a)
    t = 70.0(9.8-.4)
    = 685 N

    looks good?
  2. jcsd
  3. Jun 15, 2005 #2
    Looks fine to me.
  4. Jun 15, 2005 #3
    Might just be me, but if he goes up at 0.4 then g is -9.8 because it is acting in the opposite direction. If you think about it in the direction as g is 9.8 then is acceleration is going to be -0.4.

    So the second one looks good to me. :smile:

    The Bob (2004 ©)
  5. Jun 15, 2005 #4
    As he goes up he pulls down on the rope.
  6. Jun 16, 2005 #5
    I see. :smile:

    Cheers. :biggrin:

    The Bob (2004 ©)
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