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Calculating Angle Between E-Field and Current Vectors in Anisotropic Mat.
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[QUOTE="Fred Wright, post: 6392822, member: 570722"] I agree with your result for part i). For part ii), since you already found the conductivity tensor, you can tell immediately by inspection that the tensor is diagonal with ##\sigma_{xx} = \sigma_{yy}=\sigma_0=\sigma## and ##\sigma_{zz}=\sigma_0 + \sigma_1##. By making the coordinate transformation you are asked to solve, $$ \begin {pmatrix} \sigma & 0 & 0 \\ 0 & \sigma & 0 \\ 0 & 0 & \sigma_0 + \sigma_1 \\ \end {pmatrix} \begin {pmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & \gamma \\ \end {pmatrix} = \begin {pmatrix} \sigma & 0 & 0 \\ 0 & \sigma & 0 \\ 0 & 0 & \sigma \\ \end {pmatrix} $$ [/QUOTE]
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Calculating Angle Between E-Field and Current Vectors in Anisotropic Mat.
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