An aluminum can, with negligible heat capacity, is filled with 485 g of water at 0°C and then is brought into thermal contact with a similar can filled with 517 g of water at 48.5°C. Calculate the change in entropy of the system if no heat is exchanged with the surroundings.(adsbygoogle = window.adsbygoogle || []).push({});

1) I find avg temp, which turns out to be: ~298

2) I calc change in temp for both sides, and find Q. (deltaT)(4.184)(mass)

3) Divide each Q (they're the same, with one being negative) by each starting temperature

4) I come up with .163599 J/K, which is wrong

Where am I messing up? I have 4-5 problems identical to this but can't figure any of them out!!!

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Calculate the change in entropy of the system

**Physics Forums | Science Articles, Homework Help, Discussion**