- #1

nokia8650

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(a) Find the vector A to B.

(b) Calculate the cosine of OAB.

(c) Show that, for all values of t, the point P with position vector ti + 2tj + (2t - 9)k

lies on the line through A and B.

I am having problem with parts b and c.

For a) - A to B is (3i + 6j + 6k)

for b), I get the cosine of the angle using the dot product formula to be positive 2/3 - however the markscheme says negative 2/3.

I am really stumped with c - I don't know how to tackle this problem. I can find the equation of the line AB to be r= (4i + 8j - k) + t(i + 2j + 2k). However, I don't understand how this ties into the question. I can see that the "t" coefficients are the same, but where does the -9 in the question come from?

Thanks