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Biology and Chemistry Homework Help
Calculate the final temperature of the solution
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[QUOTE="JessicaHelena, post: 6073048, member: 643879"] [h2]Homework Statement [/h2] Consider the dissolution of CaCl2. CaCl2([I]s[/I]) [ATTACH=full]232244[/ATTACH] Ca2+([I]aq[/I]) + 2 Cl-([I]aq[/I]) Δ[I]H[/I] = -81.5 kJ A 10.6-g sample of CaCl2 is dissolved in 109 g of water, with both substances at 25.0°C. Calculate the final temperature of the solution assuming no heat lost to the surroundings and assuming the solution has a specific heat capacity of 4.18 J/°C · g. [h2]Homework Equations[/h2] Q=mcΔT [h2]The Attempt at a Solution[/h2] I had thought Q=ΔH = -81.5kJ = -81.5 x 10^3 J the mass would be 10.6+109 g and since the solution overall has a heat capacity of 4.18 J/°Cg, I plugged the numbers in: 81.5 x 10^3 = (10.6+109)x4.18x(T_f-25) Then I got T_f = 188 °C, which is wrong, but I don't understand why. I don't have much time until the assignment is due, so could someone please help me out? Thank you! [/QUOTE]
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Calculate the final temperature of the solution
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