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Calculate the flux that passes through the floor

  • Thread starter figs
  • Start date
  • #1
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A house has a floor area of 200 m^2 and an outside wall that has an area of 50.0 m^2. The earth's magnetic field here has a horizontal component of 2.58×10^-5 T that points due north and a vertical component of
4.14×10^-5 T that points straight down, toward the earth. a)Determine the magnetic flux through the wall if the wall faces north. b)calculate the flux that passes through the floor.

a)
flux=BAcos(theta)
=(4.14*10^-5)(50 m^2)(cos 90 deg)
=0 Wb

b)
flux=BAcos(theta)
=(2.58*10^-5)(200 m^2)(cos 0 deg)
=5.16*10^-3 Wb

I'm not sure what I did wrong.
 

Answers and Replies

  • #2
dextercioby
Science Advisor
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At point a) it's the horizontal component which gives the nonzero flux...

As for point b),it's viceversa,only the vertical one does.

Daniel.
 
  • #3
Astronuc
Staff Emeritus
Science Advisor
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A house has a floor area of 200 m^2 - normal points vertical - a vertical component of 4.14×10^-5 T that points straight down,

An outside wall has an area of 50.0 m^2. The wall's normal is horizontal, The earth's magnetic field here has a horizontal component of 2.58×10^-5 T that points due north.
 
  • #4
27
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im still in the dark about this vertical horizontal component
do i need to find some magnitude before i find the flux?
 

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