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Calculate The Flux

  1. Nov 4, 2007 #1
    1. The problem statement, all variables and given/known data

    A horizontal desk surface measures 4.3 m by 2.0 m. If the Earth's magnetic field has magnitude 0.32 mT and is directed 45° below the horizontal, what is the magnetic flux through the desk surface?

    2. Relevant equations

    Flux = B*A*Cos(a)

    Where A is the area, B is the magnetic field,

    3. The attempt at a solution

    Flux = B*A*Cos(a)
    = (.32E-3 T) * (4.3*2.0 m^2) * ( Cos(45) )
    = 0.00194596 T*m

    However, the my solution isn't correct and I'm convinced that I'm not doing anything incorrectly.
  2. jcsd
  3. Nov 5, 2007 #2


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    Homework Helper

    I don't see anything wrong with your calculation either (other than that the units of flux should be T·(m^2).

    I am a bit troubled by the value given for the magnetic field strength. For Earth, this value should be more like 30-60 microteslas or 0.03-0.06 mT. Are you sure about the location of the decimal point in the problem?
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