Calculate the linear acceleration of a car

  • Thread starter nautica
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  • #1
nautica
a) Calculate the linear acceleration of a car, the 0.300 m radius tires of which have an angular acceleration of 10 rad/sec^2, assume no slippage.

a = ???
r = 0.30 m
Rot acc = 10.0 rad/s^2

a = r * (rotational acc)
a = .3 m * 10 rad/s^2
a = 3.0 m/s^2

b) How many revolutions do the tires make in 2.5 s if they start from a rest???

V final = 10 rad/s^2 * 2.5 s * 1 rev / 2pie rad = 3.98 rev/s

(Vf - Vo)/2 should give average velocity so

(3.98 rev/s)/2 = 1.98 rev/s

1.98 rev/s * 2.5 s = 4.97 rev

c) What is their final angular velocity???

W = Wo + (rotational acc) * time

W = 10 rad/s^2 = 25 rad/s

d) What is the final velocity of the car???

v = (.3m) * (25 rad/s) = 7.5 m/s

Could someone check this please - I feel relatively confident - but you will not hurt my feelings if you tell me I am wrong.

Thanks
Nautica
 

Answers and Replies

  • #2
jamesrc
Science Advisor
Gold Member
476
1
Your answers are correct. You could have done part b in one step if you used Δθ = ωo*t + .5*α*t^2 and there was a typo in the third line of your solution to part c, but that's neither here nor there.
 
  • #3
nautica
I see that now

Thanks
Nautica
 
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