Calculate the magnitude and direction of the electric field intensity

  • #1
Quick Physics Help....

X and Z represent point charges of -2.4 x 10^-3 C and +3.3 x 10^-2 C respectively. Calculate the magnitude and direction of the electric field intensity at point Y, 5.00 cm from X and 8.50 cm from Z (they all live in a line).

Can sumone help me?
 

Answers and Replies

  • #2
650
1
Apply the superposition principle i.e Electric field at point will be equal to electic field due to X + due to Z.
 
  • #3
So does 4.974 x 10^10 look good?
 
  • #4
650
1
you didn't tell about the location of point ,is it left of X or right of Z or in between which will decide mag+dir
 
  • #5
X -----5.0------- Y----------8.5--------Z
 
  • #6
650
1
direction will be towards YX and magnitude=9x10^9(2.4x10^-3/5x 10^-2+ 3.3 x 10^-2/ 8.5x10^-2
=3.92 x 10^9
 
  • #7
Ah...... It all makes sense now.....
THanks for the help!
 

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